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Took me some time to prove
But I did.
Theorem distr_rev : forall l1 l2 : natlist, rev (l1 ++ l2) = (rev l2) ++ (rev l1).
But I did.
Theorem distr_rev : forall l1 l2 : natlist, rev (l1 ++ l2) = (rev l2) ++ (rev l1).